Hii sir, I wants to get the Previous year question paper of the Basic Engineering BSNL TTA Examination will you please provide it ?

The BSNL conducts the TTA Exam for Recruitment of the Telecom Technical post
the question paper of the Basic Engineering of the TTA Exam is given below



1. X2 - 4X - 2Y + Y2 = 4 represents a circle with
(a) radius = 3
(b) radius = 4
(c) radius = 2
(d) radius = 5
2. Which of these represent two parallel lines:
(a) Y - 4X - 4 = 0
(b) Y + AX - 4 = 0
(c) Y - 4X - 1 =0
(a) (i) and (ii)
(b) (i) and (iii)
(c) (ii) and (iii)
(d) None of these.

3. The conjugate of complex numbers 3 + 2j is
(a) 3 - 2j
(b) 2 + 3j
(c) 2 - 3j
(d) 3 + 4j

4. A Square matrix each of whose diagonal element is 1 and each of the non-diagonal element is zero is
called
(a) Null matrix
(b) Unit matrix
(c) Diagonal matrix
(d) Orthogonal matrix
(a) 1
(b) 9
(c) 15
(d) 21

6. The charge of an electron is equal to
(a) 1.6 x 10-16 C
(b) -1.6 x 10-16 C
(c) 1.6 x 1019 C
(d) -1.6 x 1019 C

7. The potential energy of a charged conductor is
(a) 1/2 CV2
(b) 1/2 QV
(c) Both (a) and (b)
(d) None of these

8. Capacitors are mainly used in
(a) Electrical instruments
(b) Storage of electrical energy
(c) Overcoming voltage fluctuations
(d) All the above

9. Two capacities of 4 µF and 12 µF are joined in parallel. The total capacitance is
(a) 8 µF
(b) 16 µF
(c) 3 µF
(f) 2 µF

11. A current of 12 A is passing through a pure resistive circuit when the potential difference of 60 volt
is applied across it, if the potential difference applied is reduced to 12 V, the current would be
(a) 12/5 A
(b) 60 A
(c) 12 A
(d) 2 A
12. Which of these normally used household electrical bulbs will be having maximum resistance.
(a) 100 Watt bulb
(b) 50 Watt bulb
(c) 200 Watt bulb
(d) 25 Watt bulb

13.The distance of point P (4, 3) from the origin will be
(a) 7
(b) 1
(c) 5
(d) 9

14. The slope of the line passing from points (7, 3) and (5, 1) is
(a) 1
(b) 2
(c) 3
(d) 4

15. A line perpendicular to line 3x + 4y + 5 = 0 can be
(a) 4x + 3y + 4 = 0
(b) 4x - 3y + 3 = 0
(c) 3x - 4y + 5 = 0