#1
January 6th, 2017, 04:58 PM
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KOH + HCL Reaction
Hi I would like to know what happens when Potassium hydroxide react with hydrogen chlorideas wel as the balanced equation?
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#2
January 6th, 2017, 05:38 PM
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Re: KOH + HCL Reaction
A hydroxide alludes to the OH-polyatomic particle and is shaped when an oxygen makes a covalent bond with one hydrogen (be that as it may you would not see such particles free in nature as they would all the more presumably be in mixes). Potassium hydroxide (KOH) is shaped when Potassium frames ionic bonds with OH-particles while Potassium Oxide (K2O) is framed when potassium shapes ionic bonds with the Oxide (O2-) particles. Hydrochloric corrosive + Potassium Hydroxide - > Potassium Chloride + Water i.e. HCl(aq) + KOH (aq) - > KCl (aq) + H2O (l) This response is a balance response and happens when a corrosive (HCl) responds with a base (KOH). HCl + KOH >> KCl + H2O acid + base >> salt + water KOH is potassium hydroxide K2O is potassium oxide Balanced equation: HCl + KOH = KCl + H2O Reaction type: double replacement Reaction Stoichiometry Compound Coefficient Molar Mass HCl 1 36.46094 KOH 1 56.10564 KCl 1 74.5513 H2O 1 18.01528 |
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