Hi friend here I am giving you the NIFT Management last year questions

GENERAL ABILITY TEST

1. [b] Let B = x, then C = 2x & A = 2/3 x. Therefore A: B: C = (2/3) x: x: 2x = (2/3): 1: 2 = 2: 3: 6
2. [b] Required number = 1 X 2 X 3 X 4 = 24
3. [d] Alcohol content = (20/100) X 20 = 4 liters and therefore water is 16 liters. In the new mixture, alcohol
content=4 liters and water is16+5=21liters.Hence percentage of alcohol in new mix=(4/25)X100= 16%.
4. [d] (5a+3b)/ (5a-3b)=[(5a/b) +3]/ [(5a/b) -3]=[5 X (2/5) +3]/ [5 X (2/5) -3]=5/ (-1)= -5
5. [c] Money collected = 5929. Therefore, The number of members = √5929 = 77
6. [d] Ram + Lakhan + Pavan = 67 X 3 = 201, Ram + Lakhan = 62 X 2 = 124,
Lakhan + Pavan = 68 X 2 = 136, Hence, Lakhan = 124 + 136 – 201 = 260 – 201 = 59 kg.
7. [c] The sum of remaining two = (8 X 18 – 6 X 15) = 54. The average of these two numbers = 54 / 2 = 27
8. [a] For ‘x’ length of fabric, (30 / 100) x = 126. Or x = (126 X 100) / 30 = 420
9. [b] Let, son’s age = x, then Mr. Chopra’s age= 4x. 5 years ago, 9 (x-5) = 4x-5 or x = 8.
Therefore, Mr. Chopra’s present age = 4x = 32
10. [a] Required % = [{33 / (100 + 33)} X 100] = 24.8%
11. [b] New price = 110% of 80% of 9600 = (110 X 80 X 9600) / (100 X 100) = 8448.
12. [b] Reduction in consumption = [{20 / (100 + 20)} X 100]% = 16.67%
13. [b] 40% of x = 178 + 22 (since he failed by 22 marks to get 40%) or (40/100) x = 200 or x = 500.
14. [c] For a distance of x, difference in timings = 20 min = 1/3 hour.
Hence, x/3 – x/4 = 1/3 or 4x – 3x = 4 or x = 4 km
15. [b] For original price of 100, new price = 80. So, increase on 80 is 20.
Hence, increase on 100 should be = (20 / 80) X 100 = 25%
16. [d] 17. [b] 18. [a] 19. [a] 20. [b] 21. [d]
22. [c] 23. [d] 24. [b] 25. [d] 26. [d] 27. [a]
28. [a] 29. [a] 30. [b] 31. [d] 32. [c] 33. [b]
34. [d] 35. [c] 36. [a] 37. [a] 38. [b] 39. [c]
40. [b] 41. [b] 42. [d] 43. [d] 44. [c] 45. [a]
46. [c] 47. [d] 48. [c] 49. [a] 50. [c] 51. [a]
52. [c] 53. [c] 54. [b] 55. [d] 56. [a] 57. [c]
58. [b] 59. [c] 60. [d]
61. [d] 21 % of the families use Cinthol ⇒ 1500 x (21 / 100) = 315 families use Cinthol.
62. [d] By decreasing Lux by 5 % use we get 27 % ⇒ 1500 x (27 / 100) = 405 families use Lux.
After increasing Santoor by 5 % use get 19 % ⇒ 1500 x (19 / 100) = 285 families use Santoor.
Difference is 405 – 285 = 120.
63. [b] Total percentage of families using Pears is 17. ∴ 1500 x 17/100 = 255
64. [d] 10 % of people use Rexona ⇒ 1500 x 10/100 = 150. 14 % of people use Santoor
⇒ 1500 x 14/100 = 210 ∴ Number of families use Rexona and Santoor is 150 + 210 = 360
65. [c] Dove is used by 5 % of people, ∴It is the soap used by minimum number of families
66. [b] In reverse order, ZYX …NM _ K
67. [d] Here, mouth is the nose & one smells through nose.
68. [b] Since J is the grandson of K, K is grandson or grandmother of J and not father.
69. [c] Area = a*(3/2) *a = (3/2) a2
70. [d] 7 X 7 = 49, 6 X 6 X 6 = 216, 5 X 5 X 5 X 5 = 625, 4 X 4 X 4 X 4 X 4 = 1024, 3 X 3 X 3 X 3 X 3 = 729
71. [b] The plural of cloth is clothes the plural of lady is not women but ladies.
72. [b] 2 pens + 1 pencil = 15 ...... (from B). Multiplying the above equation by 4 we get,
8 pens + 4 pencils = 60. This is the required answer. ∴ Only statement B is sufficient.
73. [d] In statement B it is given that Ramesh's sister is 10 years old but how many years is Ramesh elder to
his sister is not given. ∴ Both the statements are not sufficient.
74. [c] In statement A, it is given that y is grandfather of x. It means x is either grandson or granddaughter to
y. In statement B it is given that z is the wife of x that means x is male. ∴From both the statements A
and B we can say that x is grandson to Y.
75. [d] The alphabets in the given word are replaced by the alphabets that come before them in the series. Ex.
A is replaced by Z, B by A and so on.
76. [b] 26.1.91 = Monday, 365 = 52 Weeks + 1. It is 1st day after 52 weeks. Hence it will be Monday only.
77. [a] 2 + 12
= 3, 3 + 22
= 7, 7 + 32
= 16, 16 + 42
= 32, 32 + 52
= 57
78. [b] The numbers are multiplied by 3 to get the next number, i.e., 54 X 3 = 162


NIFT Management Last year Questions