Molarity portrays the connection between moles of a solute and the volume of an answer. To compute molarity, you can begin with moles and volume, mass and volume, or moles and milliliters. Connecting these factors to the fundamental recipe for figuring molarity will give you the right answer.

Know the essential recipe for ascertaining molarity. Molarity is equivalent to the quantity of moles of a solute partitioned by the volume of the arrangement in liters.[1] As such, it is composed as: molarity = moles of solute/liters of arrangement

50.0 ml of a standard arrangement is expected to kill 50.0 ml of 0.100 M H2SO4.

Moles H2SO4 = 0.0500 L x 0.100 M = 0.00500

H2SO4 + 2 NaOH = Na2SO4 + 2 H2O

moles NaOH required = 0.00500 x 2 =0.0100

Molarity NaOH = 0.0100 mol/0.0500 L=0.200 M

moles HCl = 0.0500 L x 0.100 M= 0.00500

moles NaOH required = 0.00500

V = 0.00500/0.200 M=0.0250 L = 25.0 mL

How would you discover the molarity of NaOH?

The molarity of the HCl can now be dictated by the meaning of molarity. The molarity of the NaOH is dictated by partitioning the moles of KHP by the volume of NaOH utilized. Utilizing this last recipe to compute the grouping of your NaOH (ensure you change over your volume to litters by separating by 1000 mL/L).

Please find the file attached below which has the detailed explanation on finding the molarity of NaOH.

Molarity of NaOH

Attached Files

Molarity of NaOH.pdf (41.4 KB, 196 views)