The topics of the Geometry Section that is Asked in the CAT Exam is as follow :
CAT Geometry questions typically present problems based on Lines, Angles, Triangles, Spheres, Rectangles, Cube, Polygons, Circles, Pythagorean Theorem, Distances, Cubes, Prisms, Pyramids, and Cylinders. Sometimes you may also find Trigonometry and Coordinate Geometry.

Here I am giving you the Sample questions in the Geometry that is As follow :

Q1. Find out the number of triangles in an octagon.
1. 326 2. 120 3. 56 4. Indeterminate

Answer : 3
Solution: No. of triangles =nC3 where n stands for the no. of points.
In this case, n = 8 => number of triangles =8C3 = 56

Q2. Determine the equation of a line, the intercepts of which are twice those of the line 3x – 2y – 12 = 0.
1. 3x – 2y = 24 2. 2x – 3y = 12
3. 2x – 3y = 24 4. None of these

Answer : 1

Solution:
If x = 0, y = – 6
Thus, the y intercept is – 6
Put y = 0, in that case x = 4
Hence the x intercept = 4
Thus, the intercepts of the required line are 8 and – 12. So the equation of the line is
(x/8) + (y/-12) = 1-12x + 8y = -96
3x – 2y = 24

Q3. A square ABCD is inscribed within a given circle. If the perimeter of the square is 16, the approximate diameter of the circle will be
1. 4 2. 6 3. 8 4. 12
Answer : 2

Solution:

If the perimeter of the square is 16, each side must measure 4 units. It means that the diameter of the circle is the hypotenuse of an isosceles right-angled triangle having short sides of length 4. We see that the diameter is longer than one side of the square. Now we know that it must be greater than 4, which helps us eliminate answer 1.
We can also see the diameter is shorter than two of the sides of the square added together and so we know it must be less than 8 which eliminates 3 and 4 which are greater than or equal to 8. This only leaves answer 2 which must be the correct answer.


Q4. All interior angles of a regular polygon measure 120 degrees each more than each exterior angle. How many sides can you count in the said polygon?
1. 6 2. 8 3. 12 4. 3

Answer : 3

Solution:

Let there be an exterior angle Ao. In that case, each interior angle will be 120 + Ao. We already know that in a regular polygon, the sum of an exterior and interior angle is always = 180o. Thus A + 120 + A = 180 => A = 30o.
Number of sides in a polygon = 360 / each exterior angle = 360/30 = 12