Here I am giving you solved question paper for infosys placement examination in PDF file attached with it so you can get it easily.

1. Select a figure from amongst the Answer Figures which will continue the same series
as established by the five Problem Figures.
Problem Figures:
Answer Figures:
(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)
A. 1
B. 2
C. 3
D. 4
E. 5
Ans: C Page 3

Explanation: In each step, element at the upper-right position gets enlarged, inverts
vertically and reaches the lower-left corner; the existing element at the lower-left
position, is lost and a new small element appears at the upper-right position.
2. Select a figure from amongst the Answer Figures which will continue the same series
as established by the five Problem Figures.
Problem Figures:
Answer Figures:
(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)
A. 1
B. 2
C. 3
D. 4
E. 5
Ans: B
Explanation: In each step, the elements move in the sequence.
3. Select a figure from amongst the Answer Figures which will continue the same series
as established by the five Problem Figures.
Problem Figures:
Answer Figures:
(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)
A. 1
B. 2
C. 3
D. 4
E. 5
Ans: D
Explanation: In each step, the CW-end element moves to the ACW-end position.
4. Select a figure from amongst the Answer Figures which will continue the same series
as established by the five Problem Figures.
Problem Figures:
Answer Figures:
(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)
A. 1
B. 2
C. 3
D. 4
E. 5
Ans: A
Explanation: The ‘x’ moves one step and two steps ACW alternatively and a symbol is
added each time it moves one before and the other after alternatively.
5. Select a figure from amongst the Answer Figures which will continue the same series
as established by the five Problem Figures.
Problem Figures:
Answer Figures:
(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)
A. 1
B. 2
C. 3
D. 4
E. 5
Ans: E Page 4

Explanation: In each step, the figure rotates ACW and the trapezium gets inverted.
The other symbol gets replaced by a new one alternatively.
Directions (Questions 6-10) Each of the following Questions consists of five options.
Choose the best option that suits the question given.
6. Nithin was counting down from 32. Sumit was counting upwards the numbers starting
from 1 and he was calling out only the odd numbers. What common number will they
call out at the same time if they were calling at the same speed?
A. 19
B. 21
C.22
D.They will not call out the same number
E. None of these.
Ans: D
Explanation:
Nithin: 32 31 30 29 28 27 26 25 24 23 22 21 20…..
Sumit: 1 3 5 7 9 11 13 15 17 19 21 23 25…
Clearly it is seen that they never call out same nmber at the same time.
7. Radha moves towards South-east a distance of 7 km, then she moves towards West and
travels a distance of 14m. From here, she moves towards North-west a distance of 7 m
and finally she moves a distance of 4 m towards East and stod at that point. How far is
the starting point from where she stood?
A. 3 m
B. 4m
C.8 m
D10 m
E.11 m
Ans
Explanation: The movements of Radha are shown as below:
Clearly Radha’s distance from starting point O = OD = (OC –CD) =(AB-CD)
= (14-4) m = 10 m
8. In a certain office, 1/3 of the workers are women, ½ of the women are married and 1/3
of the married women have children. If 3/4 th of the men are married and2/3 rd of the
married men have children, what part of workers are without children?
A. 5/18
B. 4/9
C. 11/18
D17/18
E.17/36
Ans: C
Explanation: Let total no. of workers be x
Number of women = x/3 and number of men = 2x/3
Women married=1/2 * x/3 = x/6
Women having children = 1/3 *x/6 =x/18
Married Men =3/4 *2x/3 = x/2
Men having Children =2/3 * x/2 = x/3
Workers with children = x/3 + x/18 = 7x/18
Hence, workers without children = x- 7x/18 = 11x/18 Page 5

9. A, P, R, X, S and Z are sitting in a row. S and z are in the centre. A and P are at the
ends. R is sitting to the left of A. Who is to the right of P?
A. P
B. A
C.X
D.S
E.Z
Ans: C
Explanation : The seating arrangement is as follows :
P
X
S
Z
R
A
Hence , right of P is X.
10. Introducing a boy, a girl said, "He is the son of the daughter of the father of my
uncle." How is the boy related to the girl?
A. Brother
B. Nephew
C. Uncle
D. son in law
E. grand father
Ans: A
Explanation:
The father of the boy's uncle → the grandfather of the boy and daughter of the
grandfather → sister of father.
Directions (Questions 11-12): Each Question Given Below has a problem and two
statements numbered I and II giving certain Information. You have to decide if the
information given in the statements is sufficient for answering the problem. Indicate
your answer as
(i) if data in statement I alone are sufficient to answer the question;
(ii) if data in statement II alone are sufficient to answer the question;
(iii) if data either in I or II alone are sufficient to answer the question;
(iv) if the data even in both the statements together are not sufficient to answer the
question;
(v) if the data in both the statements are needed.
11. Is Anil taller than Sachin?
I. Dinesh is of the same height as Arun and Sachin.
II. Sachin is not shorter than Dinesh.
A. i
B. iii
C. ii
D. v
E. iv
Ans: A
Explanation: From statement I, we can conclude that Dinesh, Arun and Sachin are of
same height. So, Arun is not taller than Sachin. So, only statement I is sufficient to
answer the question.
12. In a certain code language, ‘13’ means ‘stop smoking’ and ‘59’ means ‘injurious
habit’. What is the meaning of ‘9’ and ‘5’ respectively in that code?
I. ‘157’ means ‘stop bad habit’
II. ‘839’ means ‘smoking is injurious’.
A. ii
B. iii
C. v
D. iv
E. i Page 6

Ans: B
Explanation: ‘59’ means ‘injurious habit’ and ‘157’ means ‘stop bad habit’. Hence
common letter ‘5’ denotes ‘habit’. Hence ‘9’ is obviously ‘injurious’. So I alone can be
sufficient. Also, ‘59’ is ‘injurious habit’ and ‘839’ is ‘smoking is injurious’ from which it
can be implied that ‘9’ is ‘injurious’. Hence II alone can also be sufficient. Hence either I
or II alone can be sufficient.
Directions (13- 15): In the following problem, there is one question and three
statements I, II and III below the question. You have to decide whether the data
given in the statements is sufficient to answer the question. Read all the statements
carefully and find out the probable pair which can be sufficient to answer the
question.
13. Five persons --- A, B, C, D and E are sitting in a row. Who is sitting in the middle?
I. B is in between E and C.
II. B is to the right of E.
III. D is in between A and E.
A. I and II together
B. II and III together
C. I and III together
D. I, II and III together
E. Data insufficient.
Ans: D
Explanation:
From I, the order is E, B, C or C, B, E.
From II, the order is E, B.
From III, the order is A, D, E.
Combining all the three, we get the order as: A, D, E, B, C.
Clearly, E is sitting in the middle.
Hence all the three statements are required.
14. Four Subjects --- Physics, Chemistry, Mathematics and Biology were taught in four
consecutive periods of one hour each starting from 8.00 a.m. At what time was the
Chemistry period scheduled?
I. Mathematics period ended at 10.00 am which was preceded by Biology.
II. Physics was scheduled in the last period.
III. Mathematics period was immediately followed by Chemistry.
A. Only I
B. Only I or II
C. Only II
D. II and III together.
E. I and II together or I and III together
Ans: E
Explanation: From I and II we conclude that Mathematics period began at9.00 a.m.,
Biology period began at 8.00 a.m. and Physics period began at 11.00 a.m. So, the
Chemistry period began at 10.00 a.m.
From I and III, it is clearly seen that Mathematics period ended at 10.00 a.m. followed by
Chemistry to start at 10.00 a.m.
15. How many sons does Sharma have?
I. Saurav and Aditya are brothers of Sonali.Page 7

II. Ayesha is sister of Sharmila and Aditya.
III. Ayesha and Sonali are daughters of Sharma.
A. I and II only.
B. II and III together.
C. I, II and III together
D. I, II, III together are not sufficient
E. I and III together
Ans: C
Explanation: From I, Saurav, Aditya and Sonali are siblings. From II, Ayesha, Sharmila
and Aditya are siblings. It implies that Saurav, Aditya, Ayesha, Sharmila and Sonali are
siblings. This is supported by III.
Directions (Questions 16-20): The following table shows the number of new
employees added to different categories of employees in a company and also the no
of employees from these categories who left the company ever since the foundation
of the company in 1995.
16. During the period of 1995 and 2000, the total no of operators who left the company is
what percent of the total number of Operators who joined the company?
A. 19%
B. 21%
C. 27%
D. 29%
E. 32%
Ans: D
Explanation: Total no. of operators who left the company during 1996 to 2000
= (104 + 120 + 100 + 112 + 144) = 580.
Total No. of Operators who joined the company during 1996 to 2000
= (880 + 256 + 240 + 208 + 192 + 248) = 2024.
Hence, required Percentage = (580/2024 * 100) = 28.66% = 29%
17. For which of the following categories the percentage increase in the number of
employees working in the company from 1996 to 2000 was maximum?
A. Managers
B. Technicians
C. Operators
D. Accountants
E. Peons.
Ans: A
Explanation:
No. of managers in 1995 = 760Page 8

No. of managers by 2000 = (760 + 280 + 179 + 145 + 160 + 193) – (120 + 92 + 88 + 72
+ 96) = 1252.
Hence, percentage of increase = (1262-760)/760 * 100 = 64.74%
Similarly we can calculate for the rest of employees.
18. What is the difference between total number of Technicians added to the company
and total number of Accountants added to the company during the year 1996 to 2000 at
the maximum?
A. 128
B. 112
C. 96
D. 88
E. 72
Ans: D
Explanation: (272 + 240 + 236 + 256 + 288) – (200 + 224 + 248 + 272 + 260) = 88
19. What was the total no. of peons working in the company in the year 1999?
A. 1312
B. 1192
C.1088
D.968
E.908
Ans: B
Explanation: (820 + 184 + 152 + 196 + 224) – (96 + 88 + 80 + 120) = 1192
20. What is the pooled average of all employees in the year 1997?
A. 1325
B. 1285
C. 1265
D. 1235
E. 1195
Ans: E
Explanation:
Managers: (760 + 280 + 179) – (120 + 92) = 1007
Technicians: (1200 + 272 + 240) – (120 + 128) = 1464
Operators: (880 +256 +240) – (104 + 120) = 1152
Accountants: (1160 +200 +224) – (100 + 104) = 1380
Peons: (820 + 184 + 152) – (96 + 88) = 972
Hence pooled average of 5 categories = (1007 + 1464 + 1152 + 1380 + 972)/5 = 1195
Directions (Questions 21-25): The following questions are based on the information
given. Choose the appropriate answer that suits the question based on the
information.
A cube is cut in two equal parts along a plane parallel to one of its faces. One piece is
then colored red on the two larger faces and green on remaining. While the other is
colored green on two smaller adjacent faces and red on the remaining. Each is then cut
into 32 cubes of same size and mixed up.
21. How many cubes have only one colored face each?
A. 32
B. 8
C. 16
D. 24
E. 0
Ans: C
Explanation: Page 9

8 from first half and 8 from second half of the main cube. Hence total of 16 cubes.
22. What is the number of cubes with at least one green face on each?
A. 36
B. 32
C. 38
D. 48
E. 40
Ans: C
Explanation:
24 from I and 14 from II
23. How many cubes have two red and one green face on each?
A. 16
B. 12
C. 8
D. 4
E. 0
Ans: D
Explanation: Page 10

None from I and 4 from II
24. How many cubes have no colored face at all?
A. 32
B. 24
C. 16
D. 8
E.0
Ans: E
Explanation:
There is no cube in all, when all the faces are enclosured.
25. How many cubes have each one red and another green?
A. 0
B. 8
C.16
D.24
E.32
Ans: D

Directions (Questions 26-30): In each of the following questions two statements are
given and these statements are followed by two conclusions numbered (1) and (2). You
have to take the given two statements to be true even if they seem to be at variance from
commonly known facts. Read the conclusions and then decide which of the given
conclusions logically follows from the two given statements, disregarding commonly
known facts.
26. Statements: Some papers are pens. All the pencils are pens.
Conclusions:
1. Some pens are pencils.
2. Some pens are papers.
A. Only (1) conclusion follows
B. Only (2) conclusion follows
C. Both (1) and (2) follow
D. Either (1) or (2) follows
E. Neither (1) nor (2) follows
Ans: C
Explanation:
27. Statements: Some dogs are bats. Some bats are cats. Page 12

Conclusions:
1. Some dogs are cats.
2. Some cats are dogs
A. Only (2) conclusion follows
B. Both (1) and (2) follow
C. Either (1) or (2) follows
D. Only (1) conclusion follows
E. Neither (1) nor (2) follows
Ans: E
Explanation:
28. Statements: All the windows are doors. No door is a wall.
Conclusions:
1. Some windows are walls.
2. No wall is a door.
A. Either (1) or (2) follows
B. Only (2) conclusion follows
C. Both (1) and (2) follow
D. Neither (1) nor (2) follows
E. Only (1) conclusion follows
Ans: B
Explanation: Page 13

29. Some actors are singers. All the singers are dancers.
Conclusions:
1. Some actors are dancers.
2. No singer is actor.
A. Only (1) conclusion follows
B. Only (2) conclusion follows
C. Either (1) or (2) follows
D. Neither (1) nor (2) follows
E. Both (1) and (2) follow
Ans: A
Explanation:
30. Statements: All the pencils are pens. All the pens are inks.
Conclusions:
1. All the pencils are inks.
2. Some inks are pencils.
A. Only (2) conclusion follows
B. Only (1) conclusion follows
C. Either (1) or (2) follows
D. Both (1) and (2) follow
E. Neither (1) nor (2) follows
Ans: D
Explanation

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