Will you please help me here to get the JEE Advanced Exam Paper, so hat I can solve it and prepare hard for it?

Don’t worry I will get the JEE Advanced Exam Paper, so that it would be easy for you to prepare hard and solve it easily.

Here is the exam paper

A metal surface is illuminated by light of two different wavelengths 248nm and 310 nm. The maximum speeds of the photoelectrons corresponding to these wavelengths areu1 and u2,respectively. If the ratio 1:2=2:1and hc = 1240 eV nm, the work function of the metal is nearly
(A) 3.7 eV (B) 3.2 eV (C) 2.8 eV (D) 2.5eV

Consider the partition to be rigidly fixed so that it does not move. When equilibrium is achieved, the final temperature of the gases will be (A) 550 K (B) 525 K (C) 513 K (D) 490 K

Now consider the partition to be free to move without friction so that the pressure of gases in both compartments is the same. Then total work done by the gases till the time they achieve equilibrium will be (A) 250 R (B) 200 R (C)100 R (D) −100R

When d≈a but wires are not touching the loop, it is found that the net magnetic field on the axis of the loop is zero at a height h above the loop. In that case (A)current in wire 1 and wire 2 is the direction PQ and RS, respectively and ℎ≈ (B) current in wire 1 and wire 2 is the direction PQ and SR, respectively and ℎ≈ (C)current in wire 1 and wire 2 is the direction PQ and SR, respectively and ℎ≈1.2




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Attached Files

JEE Advanced Exam Paper.pdf (2.47 MB, 54 views)