#1
January 13th, 2016, 09:21 AM
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UPSC Engineering Services Previous Papers With Answers
Sir I am looking for nthe UPSC Engineering Services Previous Papers for Mechanical and a mock test paper with answers
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#2
January 13th, 2016, 09:31 AM
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Re: UPSC Engineering Services Previous Papers With Answers
The Union Public Service Commission (UPSC) is India's central agency authorised to conduct the Civil Services Examination. Hi friend I am givng you the UPSC Engineering Services Previous Paper and Mock test paper of aptitude with the solved answers 1)A train covers a distance in 50 min ,if it runs at a speed of 48kmph on an average.The speed at which the train must run to reduce the time of journey to 40min will be. 1. Solution:: Time=50/60 hr=5/6hr Speed=48mph distance=S*T=48*5/6=40km time=40/60hr=2/3hr New speed = 40* 3/2 kmph= 60kmph 2)Vikas can cover a distance in 1hr 24min by covering 2/3 of the distance at 4 kmph and the rest at 5kmph.the total distance is? 2. Solution:: Let total distance be S total time=1hr24min A to T :: speed=4kmph diistance=2/3S T to S :: speed=5km distance=1-2/3S=1/3S 21/15 hr=2/3 S/4 + 1/3s /5 84=14/3S*3 S=84*3/14*3 = 6km 3)walking at ¾ of his usual speed ,a man is late by 2 ½ hr. the usual time is. 3. Solution:: Usual speed = S Usual time = T Distance = D New Speed is ¾ S New time is 4/3 T 4/3 T – T = 5/2 T=15/2 = 7 ½ 4)A man covers a distance on scooter .had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower he would have taken 40min more.the distance is. 4.Solution:: Let distance = x m Usual rate = y kmph x/y – x/y+3 = 40/60 hr 2y(y+3) = 9x ————–1 x/y-2 – x/y = 40/60 hr y(y-2) = 3x —————–2 divide 1 & 2 equations by solving we get x = 40 |
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